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Semmy [17]
3 years ago
11

Evaluate (2-3)^(4) - 9/3. -7 -2 1 2

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

the answer to this question is 1

gavmur [86]3 years ago
7 0

Answer:

  -2

Step-by-step explanation:

First evaluate inside parentheses

  (-1)^4 -9/3

Then do the exponentiation

  1 -9/3

Now the division

  1 -3

Finally, the sum

  -2

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Find x (x+13)(x-7)=0
alex41 [277]

So for this, we will be applying the <u>zero product property</u>, which is <u>"if a x b = 0, then either a = 0 or b = 0 or both a and b = 0"</u>. In this case, a = x + 13 and b = x - 7. Solve them separately:

x+13=0\\ x=-13\\ \\ x-7=0\\ x=7

<u>Your answer is x = -13 and 7.</u>

7 0
3 years ago
The integers X and Y fulfil the condition 2X=5Y. Which can be considered for X+Y?
KiRa [710]

Answer:

X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

Step-by-step explanation:

2X = 5Y

Y = \frac{2}{5}X

X = \frac{5}{2}Y

Hence, X + Y could equal to X + \frac{2}{5}X = 1 \frac{2}{5}X or Y + \frac{5}{2}Y = 3 \frac{1}{2}Y.

Hence, X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

6 0
3 years ago
Need help ASAP !!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B95%20%5Ctimes%2019%20%5Ctimes%205%7D%20" id="TexFormula
dimulka [17.4K]

Answer:

the answer is 9025

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

3x+100 < 5x

solve for x

subtract 3x both sides

100< 5x-3x\\100

divide by 2 both sides

50 < x

Rewrite

x> 50\ min

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
3 years ago
What is 0 + y, when y = -12
yaroslaw [1]

Answer:

-12

Step-by-step explanation:

Substituting, we get 0 - 12, Which is simply -12

3 0
3 years ago
Read 2 more answers
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