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AlexFokin [52]
2 years ago
12

Need help ASAP !!!

1" title=" \sqrt{95 \times 19 \times 5} " alt=" \sqrt{95 \times 19 \times 5} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Rudiy272 years ago
7 0

\sqrt{95 \times 19 \times 5 \\} 95 it equal 95

dimulka [17.4K]2 years ago
6 0

Answer:

the answer is 9025

Step-by-step explanation:

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Read 2 more answers
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

 f(x) = x^2 + 3x interval: [-2, 3]:
 f(-2) = x^2 + 3x  = (-2)^2 + 3(-2) = 4 - 6 = -2&#10;&#10;f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
 AVR = \frac{-20}{-5}
 AVR = 4

 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
 f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15&#10;&#10;f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
 AVR = -1

 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4&#10;&#10;f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
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