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Bingel [31]
3 years ago
7

{ }^{2} b {}^{2} - 7ab - 30" alt="2a { }^{2} b {}^{2} - 7ab - 30" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

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3/5 is greater than 2/5, so your answer goes into the negatives

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in order to solve for the value of x in the expression 6 ( x − 2 ) = 8 ( x − 9 )

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