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mars1129 [50]
3 years ago
13

A) work out the radius of the mercury, giving your answer as an ordinary number

Mathematics
1 answer:
guapka [62]3 years ago
7 0

Answer:

a. 2,440 km

b. 1.33*10^{27} kg

Step-by-step explanation:

a. Diameter of Mercury = 4.88*10^3

Radius of Mercury = ½ of its diameter = \frac{4.88*10^3}{2}

Radius of Mercury = 2.44*10^3

To convert the radius to ordinary number, multiply 2.44 by 1,000.

Radius of Mercury as an ordinary number = 2.44*1,000 = 2,440 km

b. Mass of Jupiter = 1.898*10^{27} kg

Mass of Saturn = 5.68*10^{26} kg

Difference between mass of Jupiter and mass of Saturn = 1.898*10^{27} - 5.68*10^{26} (subtract 5.68 from 1.898 = 5.68. we would retain the largest exponent, which is raised to the lower of 27.)

= 1.33*10^{27}

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X - 2y = 3<br> 5x + 3y = 2<br> The lines whose equations are shown intersect at which point?
Lady_Fox [76]

The point of intersection of the two lines is at (1,-1)

<h3>System of equation</h3>

The given system of expression is shown below

x - 2y = 3

5x + 3y = 2

The solution to the system of equation is the point of intersection

From equation 1

x = 3 + 2y

Substitute into 2

5(3+2y) + 3y = 2

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Substitute y = -1 into 3

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Hence the point of intersection of the two lines is at (1,-1)

Learn more on system of equation here: brainly.com/question/25976025

#SPJ1

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