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andre [41]
3 years ago
6

Please help meeee I’ll do anything

Mathematics
2 answers:
Anna11 [10]3 years ago
5 0

Answer:

B or second option

Step-by-step explanation:

The cost is the y-axis and the minutes is the x-axis. The + 2.00 is where the intersection of the y-axis starts.

FinnZ [79.3K]3 years ago
5 0

Answer: b is most likely to be it

Step-by-step explanation:

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A flower shop ordered 1,176 flowers to make bouquets. Each bouquet will have 12 flowers. How many bouquets can the flower shop m
nadya68 [22]

Answer: B.98

Step-by-step explanation:

all you have to do is divide 1,176 by 12.

3 0
2 years ago
Solve each of the following equations by the trial and error method : A) X- 7= -3 help some one now​
Vaselesa [24]

Answer:

X - 7 = - 3

X = - 3 + 7

X = 4

the 7 turns positive because it was moved to the other side of the symbol "=" so we reverse the sign

- becomes +

and

+ becomes -

8 0
3 years ago
How do you solve 39 equal to 1 3/10b
elena-s [515]
If 39 = (1 3/10)b, we could simplify this by writing 39 - (13/10)b.

Solve this for b by mult. both terms by (10/13):

(10*39)
----------- = (10/13)(13/10)b.  Then b = 30 (answer)
      13
5 0
2 years ago
How do you express sin x + cos x in terms of sine only?
frez [133]

Answer:

\sin x + \sqrt{1-\sin^2x}

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

  • \sin^2x+\cos^2x=1
  • \cos x=\sqrt{1-\sin^2x}

Expression: \sin x+\cos x

We get rid of cos x from expression and write as sine form.

Expression: \sin x + \sqrt{1-\sin^2x}        \because \cos x=\sqrt{1-\sin^2x}

Hence, The final expression is only sine function.

4 0
3 years ago
What is the solution to 4+5e^x+2 =11
Nezavi [6.7K]

Answer:

x =0

Step-by-step explanation:

4+5e^x+2 =11

Combine like terms

6 + 5e^x =11

Subtract 6 from each side

6-6 + 5e^x =11-6

5 e^x = 5

Divide by 5 on each side

5 e^x /5 = 5/5

e^x = 1

Take the natural log on each side

ln (e^x) = ln(1)

x = ln(1)

x =0

3 0
3 years ago
Read 2 more answers
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