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andre [41]
3 years ago
6

Please help meeee I’ll do anything

Mathematics
2 answers:
Anna11 [10]3 years ago
5 0

Answer:

B or second option

Step-by-step explanation:

The cost is the y-axis and the minutes is the x-axis. The + 2.00 is where the intersection of the y-axis starts.

FinnZ [79.3K]3 years ago
5 0

Answer: b is most likely to be it

Step-by-step explanation:

You might be interested in
Please help me understand and solve this​
ss7ja [257]

Step-by-step explanation:

just multiple them and you'll get the results and the results you got add them together

7 0
3 years ago
A car factory made 15 cars with a sunroof and 12 cars without a sunroof. What is the ratio of
zvonat [6]
5/9 because 15 + 12 = 27 and 15 are sunroofs so 15/27, I would simplify it to 5/9 but you can either have
15/27 or 5/9
5 0
2 years ago
Read 2 more answers
Please answer this and I’ll make ya
Fynjy0 [20]
It’s definitely A
Ex: f(x)=8x+2
f(x)=8(-4)+2
f(x)=-32+2
f(x)=-30
3 0
3 years ago
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
Find the 11th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.
marta [7]
I think you mean,

\sum_{i=1}^{\infty}(7i+22)

You can use the usual formula,

S_{k}=\frac{k}{2}(a_1+a_k)

That in this case is,

S_{11}=\frac{11}{2}(29+99)=704

Where I have used,

a_k=7\cdot k +22
3 0
3 years ago
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