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3 years ago

Please help, thank you!

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

Answer:

Bus B must be A) y = 40x

Step-by-step explanation:

We can tell this because it is growing at a slower rate than Bus A. As a result, we know the slope is less than 55. The only option that is less than 55 is A) 40x.

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18 *2^5t = 261 what is the solution of the equation

olchik [2.2K]

Answer:

0.772

Step-by-step explanation:

Original equation:

$18 * 2^{5t}=261$

Divide both sides by 18

$2^{5t} = 14.5$

Rewrite in logarithmic form ( $b^x=c \implies log_bc=x$ )

$log_214.5 = 5t$

Divide both sides by 5

$\frac{log_214.5}{5}=t$

Rewrite the equation so that base is 10 using change of base formula: $log_ba = \frac{log_na}{log_nb}$

$\frac{(\frac{log14.5}{log2})}{5}=y$

Keep, change, flip

$\frac{log14.5}{log2}*\frac{1}{5} = \frac{log14.5}{5 * log2}$

Use a calculator to approximate log14.5 and log2

$\frac{1.161368}{5 * 0.301029996} = t$

Multiply in denominator

$\frac{1.161368}{1.505149978} = t$

Divide two values

$t\approx 0.771596$

Round to nearest thousandth

$t\approx 0.772$

6 0

2 years ago

Simplify –36 = (-3) + 2(27 + 3 x 2) B с 21 48 108 252

IrinaK [193]

Answer:

I don't understand the question what is the quarter????

3 0

3 years ago

Can someone please help me with this. It’s due tonight and I need help

Svetlanka [38]

Step-by-step explanation:

40°

and thats an acute angle

5 0

3 years ago

Read 2 more answers

A freight train leaves a station and travels north at 60 mph. 4 hours later, a passenger train leaves on a parallel track and t

harkovskaia [24]

Answer:

first do:

60mph * 4 hours= 240mi

Let D = the distance the passenger train has to

travel to catch the freight train

Start a stopwatch when the passenger train leaves

Let t = the time on the stopwatch when they meet

Equation for freight train:

d-240=60t

Equation for passenger train:

d=100t

all together:

100t-240=60t

we can do 100t-60t because they both have (t)= 40t

40t=240 *now divide 240 by 40= 6

THEN do:

D= 100mph x 6= 600mi

They will meet 600 mi from the station

to check:

d-240=60t x 6

600-240= 360

60 x 6= 360

360=360

5 0

3 years ago

Which shows the following expression after the negative exponents have been eliminated? m^7 n^3/ mn^-1 assume m=0 and n=0

aliina [53]

Given expression is $\frac{m^7n^3}{mn^{-1}}$ .

where $m \neq 0, n \neq 0,$

Now we have to simplify this and find the next step so that negative exponent gets eliminated.

We know that when negative exponent changes sign, then it moves from numerator to denominator or from denominator to numerator as shown in the formula:

$x^{-m}=\frac{1}{x^m}$

or $\frac{1}{x^{-m}}=x^{m}$

n has negative exponent in denominator so it will move to numerator and we get:

$\frac{m^7n^3n^1}{m}$

or $\frac{m^7n^3n}{m}$

Hence final answer is $\frac{m^7n^3n}{m}$ .

8 0

3 years ago

Read 2 more answers