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photoshop1234 [79]

2 years ago

10

Given a mean of 150 and a standard deviation of 25 Define the interval about the mean that contains 95% of the data.

1 answer:

ohaa [14]2 years ago

7 0

By normal curve symmetry

<span>from normal table </span>
<span>we have z = 1.15 , z = -1.15 </span>

<span>z = (x - mean) / sigma </span>
<span>1.15 = (x - 150) / 25 </span>
<span>x = 178.75 </span>

<span>z = (x - mean) / sigma </span>
<span>-1.15 = (x - 150) / 25 </span>
<span>x = 121.25 </span>

<span>interval is (121.25 , 178.75) </span>

<span>Pr((121.25-150)/25 < x < (178.75-150)/25) </span>
<span>is about 75%</span>

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