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Rashid [163]
3 years ago
9

PLz FAAAAAAAAASTTTTTTTTT!!!!!!!! HAAALPP

Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

any value of a makes the equation true.

Step-by-step explanation:


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I need help with this tysm​
erica [24]

9514 1404 393

Answer:

  1. -51
  2. -30
  3. -60
  4. 2 or -2

Step-by-step explanation:

The function puts a minus sign on 3 times the magnitude of the input.

1. y = -|3×17| = -51

2. y = -|3×10| = -30

3. y = -|3×20| = -60

4. -6 = -|3x|

  2 = |x| . . . . divide by -3

  x = ±2 . . . . two possibilities

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The product of 11/13 and 4 is:
kirza4 [7]

Answer:

11/13 x 4 = 3 5/13

Step-by-step explanation:

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3 years ago
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Find the length of AC.
saw5 [17]

Answer:

4.3

Step-by-step explanation:

6.8^2-5.3^2=x^2

AC=4.3

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3 years ago
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skelet666 [1.2K]
Falls, rises

if it is the ONLY cable provider, then it is a monopoly
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3 years ago
In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;
Fiesta28 [93]

We have to find the expansion of (3a+4b)^{8}

We will use binomial expansion to expand the given expression, which states that the expression (a+b)^{n} is expanded as :

(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}

Now expanding (3a+4b)^{8} we get,

(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}

(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})

So, the variables are a^{5}b^{3} , b^{8} , a^{4}b^{4} , a^{8}  , [tex] ab^{7}

5 0
3 years ago
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