1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
luda_lava [24]
4 years ago
6

Please hurry and show steps :0

Mathematics
1 answer:
ch4aika [34]4 years ago
4 0

1. nth term=3n-1

  20th term=3(20)-1=60-1=59

2. nth term=-2n-4

   20th term=-2(20)-4=-40-4=-44

3. nth term=\frac{2}{3}n-\frac{2}{3}

   20th term=\frac{2}{3}(20)-\frac{2}{3}=\frac{40}{3}-\frac{2}{3}=\frac{38}{3}

4. nth term=-\frac{1}{3}n+\frac{11}{15}

   20th term=-\frac{1}{3}(20)+\frac{11}{15}=-\frac{20}{3}+\frac{11}{15}=-\frac{89}{15}

You might be interested in
What is the graph of the inequality 3x+2y>-5
Doss [256]

Answer:

The graph with solution is shown below.

Step-by-step explanation:

We need to find the x-intercept and y-intercept for given equation.

For  x-intercept , substitute y=0

Considering inequality sign as equality and simplifying,

3x+2y=-5\\3x+0=-5\\x=-\frac{5}{3} , point is (-\frac{5}{3} ,0)

Similarly,

For y-intercept , substitute x=0

We get,

3x+2y=-5\\0+2y=-5\\y=-5/2 , point is (0,-\frac{5}{2})

We locate this two points on the graph now and join them.

The joining line will be dotted as the inequality has just 'greater than' symbol. The region above the dotted line is the solution to graph.

4 0
3 years ago
The triangles are similar what is the value of x
sveticcg [70]
Is one of your options 240

8 0
3 years ago
How many solutions are there to this equation 3x(x-4)+5-x=2x-7
stich3 [128]

Answer:

  2 solutions

Step-by-step explanation:

I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...

  • x = 1
  • x = 4

__

To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:

  3x(x -4) +5 -x -(2x -7) = 0

  3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses

  3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms

  3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor

The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.

__

<em>Alternate method</em>

Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...

  d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c

  d = (-15)^2 -4(3)(12) = 225 -144 = 81

This positive value means the equation has 2 real solutions.

4 0
3 years ago
Log (x) + log (x + 5) = log (6 x + 12) <br><br> I need the answer asap
kiruha [24]
It’s b I had it in my test
5 0
4 years ago
Read 2 more answers
Solve for x. Round to the nearest tenth, if necessary.
nadya68 [22]

Answer:

x = 0.8

Step-by-step explanation:

For this problem we will be using trigonometry :

6 0
2 years ago
Other questions:
  • Can someone help i need step by step so i can understand. thank you​
    9·2 answers
  • A country population in 1993 was 94 million. In 1999 it was 99 million. Estimate the population in 2005 using the expoetential g
    8·2 answers
  • What will the temperature be in degrees Fahrenheit when it is 80° Celsius outside?
    7·2 answers
  • 16 POINTS!! The solid in the diagram has a surface area of 18 units2. If a cube is added on the green face, what will the new su
    5·1 answer
  • What is the value of sin 60
    9·1 answer
  • Help pls I’ll give extra points
    6·1 answer
  • Point A is located in which quadrant?<br> On a coordinate plane, point A is at (negative 3, 5).
    5·1 answer
  • Someone help me find the answer to this problem. 15a - 20 + 10a =
    8·2 answers
  • What is the value of h?
    9·1 answer
  • Elisabeth reads 15 of her book in 112 hours. Elisabeth continues to read at this pace. How long does it take Elisabeth to read 3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!