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3 years ago

Find the value of x. If necessary, write your answer in simplest radical form. 8 x 2

Mathematics

1 answer:

fenix001 [56]3 years ago

3 0

Answer:

8 · 2 or 8x² or 8x2

Step-by-step explanation:

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$1068.66

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3 years ago

Help please . The answer choices are A. 0 B. 1 C. 7 D. Undefined

frosja888 [35]

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3 years ago

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Thallium-210 has a half-life of 1.32 minutes. Find an equation for the percent of Thallium-210 sample that remains after t minut

Lady bird [3.3K]

Answer:

p(t) = 100%·2^(-t/1.32)

Step-by-step explanation:

The equation for exponential decay is ...

(remaining amount) = (initial amount)·2^(-t/(half-life))

Here, we can represent the percentage remaining by p(t) and the initial amount by 100%. Then, for a half-life of 1.32 minutes, the amount remaining is ...

p(t) = 100%·2^(-t/1.32) . . . . . where t is in minutes

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Alternate functional forms are possible, such as ...

p(t) = 100%·e^(-0.525112t)

p(t) = 100%·0.591489^t

4 0

3 years ago

A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a

tatuchka [14]

Answer:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

$df=n-1=15-1=14$

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

$\bar X=42.6$ represent the average nicotine content

$s=3.7$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =40$ represent the value to check

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

The statistic for this case would be:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replcing we got:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

The degrees of freedom are:

$df=n-1=15-1=14$

The p value would be:

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

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3 years ago

Rewrite this equation in Slope-intercept form (PLEASE SHOW ALL WORK)

solniwko [45]

Y=3/2x - 1/5

have a great day :)

7 0

3 years ago

Find the value of x. If​ necessary, write your answer in simplest radical form. 8 x 2

Find the value of x. If necessary, write your answer in simplest radical form. 8 x 2