Answer:
The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2
The rule of arithmetic sequence = a + d(n - 1)
Where a is the first term and n is the number of terms
So, for the even numbers between 0 and X
The first term = a = 0
d = 2
So, we need to find n at the last term which is X
∴ X = 0 + 2 ( n -1 )
∴ n - 1 = X/2
∴ n = X/2 + 1
The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)
Substitute with a and d and X
So, the sum = (n/2) * (2*0 + (n−1)*2)
= (n/2) * ((n−1)*2)
= n(n-1)
= (X/2 + 1) * (X/2)
= X/2 by (X/2 + 1)
So, The quick way to add all even numbers between 0 and X always works.
It appears to be D.SSS
.
and hello again
.
Zane
Answer: 4
Step-by-step explanation:
2 + 2 = 4
In some cases, it also equals fish.
1a) The domain is a set of all real numbers not equal to 5
1b) The domain is a set of all real numbers not equal to 4
<h3>What is the domain of the function?</h3>
Domain of a function is the set of all possible input values that make the function defined.
1a) We are given the function;
C(x) = -3²/(x - 5)
The domain will be a set of values that makes the denominator not equal to zero. Thus;
The domain is a set of all real numbers not equal to 5
1b) The function is; R(x) = 4x/(3x - 12)
The domain will be a set of values that makes the denominator not equal to zero. Thus;
The domain is a set of all real numbers not equal to 4
2a) Function is;
f(x) = (x + 8)/(2x - 1)
f(2) = (2 + 8)/(2(2) - 1)
f(2) = 10/3
f(0) = (0 + 8)/(2(0) - 1)
f(0) = -8
f(-1/2) = (-1/2 + 8)/(2(-1/2) - 1)
f(-1/2) = -15/4
2b) Function is;
r(t) = (t² + 8)/(t³ - 25t)
r(3) = (3² + 8)/(3³ - 25(3)) = -17/48
r(2) = (2² + 8)/(2³ - 25(2)) = -12/42 = -2/7
r(-1) = ((-1)² + 8)/((-1)³ - 25(-1)) = 9/24 = 3/8
Read more about Domain of function at; brainly.com/question/10197594
#SPJ1
Answer:
A simple exponential function to graph is y=2x . Notice that the graph has the x -axis as an asymptote on the left, and increases very fast on the right. Changing the base changes the shape of the graph. Replacing x with −x reflects the graph across the y -axis; replacing y with −y reflects it across the x -axis.