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Amiraneli [1.4K]
3 years ago
6

If x and y in the equations

Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0
We can let
   a = 1/(x-1)
   b = 1/(y+2)
and rewrite the equations as
   2a - b = 10
   a + 3b = -9
Using the first to write an expression for b, we get
   b = 2a - 10
Substituting this into the second equation gives
   a + 3(2a -10) = -9
   7a -30 = -9 . . . . . . . . simplify
   7a = 21 . . . . . . . . . . .add 30
   a = 3
   b = 2·3 - 10 = -4

Now, we can find x and y.
    3 = 1/(x -1)
    x - 1 = 1/3
    x = 1 1/3 = 4/3

    -4 = 1/(y +2)
    y +2 = -1/4
    y = -2 1/4 = -9/4

Then the desired sum is
    x + y = 4/3 -9/4 = (16 -27)/12
    x + y = -11/12

The appropriate choice is ..
   c. -11/12
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Step-by-step explanation:

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2 years ago
Can i please get help on this Question?
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3 0
3 years ago
Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO
Luden [163]

Answer:

La norma de los signos es para el producto de números reales, y la norma es la siguiente.

(+)*(+) = (+)

(+)*(-) = (-)

(-)*(+) = (-)

(-)*(-) = (+)

Es decir, el producto de dos números de mismo signo es siempre positivo

El producto de dos números de distinto signo es siempre negativo.

Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)

Pero en casos como:

5 - (-4)  

(esto sería: "la diferencia entre cinco y menos cuatro")

notar que podemos reescribir esto como:

5 + (-1)*(-4)

Ahora podemos aplicar la norma de los signos:

5 + 4 = 9

Donde aplicamos la norma de los signos,  

Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.

Por lo podemos concluir que la respuesta correcta es verdadero.

7 0
3 years ago
2. Which of the following is an equation? <br> A. y/9 - 3<br> B. 9 - 2<br> C. y/9 = 3<br> D. 7 + y
andrew11 [14]
An equation is something with a = sign btw and it’s C because it’s the only one with the = sign
7 0
3 years ago
Solve algebraically for x:<br> 3600 + 1.02x &lt; 2000 + 1.04x
Nata [24]

Answer:

x < 80000

Step-by-step explanation:

3600 + 1.02x < 2000 + 1.04x \\  \frac{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 1.04x <  \:  \:  \:  \:    \:  \:  \:  \:  \:  \:  \:  \:  \:  - 1.04x}{3600 - 0.02x < 2000}  \\  \\ 3600 - 0.02x < 2000 \\  \frac{ - 3600 \:  \:  \:  \:  \:  \:  \:  \:  \:  <  - 3600}{ - 0.02x <  - 1600}  \\  \\  \frac{ - 0.02x}{ - 0.02}   <  \frac{ - 1600}{ - 0.02}  \\  \\ x < 80000

4 0
3 years ago
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