Sum of the numbers in the set: 42+37+32+29+20 =160
Current mean: 160/5 = 32
Median = the valvue of the middle = 32.
New mean: 32+10= 42.
Sum of numbers in the new set = 42*8 = 336
Difference: 336 - 160 = 176
I want to include 32, so that the new median stays in 32.
So the other two numbers must add 176 - 32 = 144
I will use a smaller number than 32 and the other greater (again in order to keep the same median.
I will choose 28 and 144 - 28 = 116.
So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}
Checking:
Sum of the terms: 116+42+37+32+32+29+28+20 = 336
Mean = 336 / 8 = 42, which is 10 more than the original mean.
And the new median is (32+32)/2 = 32. The same of the original set.
A:amount of money invested in the account with 3% simple interest
B: amount of money invested in the account with 4.5% simple interest
a+b=25000 ——>a=25000-b
0.03a+0.045b=900
30a+45b=900000
2a+3b=60000
2(25000-b)+3b=60000
50000-2b+3b=60000
B=10000
A=25000-10000=15000
Answer:
(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20
(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20
Step-by-step explanation:
There are two inequalities in mind, the first of the surface and the second of the price. Always bearing in mind that the minimum are 50 of A and 20 of B.
The first
A occupies 1/2 m and B occupies 1/2 m of surface, and the limit is 100 m of surface. Thus:
(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20
The second:
A costs 5,000 and B costs 30,000, and the limit is 1,500,000. Therefore:
(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20
Answer:
x=9
y=2
z=1
Step-by-step explanation:
xx+yy=zyz
xx can be divided by 11
yy can be divided by 11
zyz can be divided by 11
3 digit multiples of 11
110
121
132...
121=zyz because z=1 and y=2
121-22=99
xx=99
x=9
z=1
y=2
Answer:
79/60 or 1 19/60 or 1.316
Step-by-step explanation:
