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3 years ago

15

Width of the rectangle.

1 answer:

kogti [31]3 years ago

4 0

I assume we have to begin with the triangle. Applying the Pyth. Thm.,
(x)^2 + (7y)^2 = (3x)^2, so that (7y)^2 = (3x)^2 - (x)^2, or 8x^2.

If (7y)^2 = 8x^2, then 7y = sqrt(8x^2) = 2sqrt(2)x. This is the width of the rectangle, i. e., width 7y = 2sqrt(2)*x.

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Which ordered pairs are solutions to the inequality y - 3x < -8?

7nadin3 [17]

Answer:

Option B,C and E are solution to given inequality $y - 3x < -8$

Step-by-step explanation:

We need to check which ordered pairs from given options satisfy the inequality $y - 3x < -8$

Ordered pairs are solutions to inequality if they satisfy the inequality

Checking each options by pitting values of x and y in given inequality

A ) (1, -5)

$-5-3(1)$

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.

B) (-3, - 2)

$-2-3(-3) < -8\\-2-9$

So, this ordered pair is solution of inequality as it satisfies the inequality.

C) (0, -9)

$-9-3(0)$

So, this ordered pair is solution of inequality as it satisfies the inequality.

D) (2, -1)

$-1-3(2)$

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.

E) (5, 4)

$4-3(5)$

So, this ordered pair is solution of inequality as it satisfies the inequality.

So, Option B,C and E are solution to given inequality $y - 3x < -8$

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AveGali [126]

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If f(x)=2x^4-3x^3+2x^2+x-3, explain how you know that the equation f(x)=0 has at least one real root between x=1 and x=2

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Answer:

Step-by-step explanation:

by theorem :

f continu in [1 , 2]

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so :

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