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dolphi86 [110]
4 years ago
12

What does 3/4 x 24 = ?

Mathematics
2 answers:
Gnesinka [82]4 years ago
5 0
18 because 3/4x24/1 equals 72/4 if you divide 72÷4 you get 18
IrinaK [193]4 years ago
4 0

Well, 1/4 of 24 gets us 6 (since 24 = 6 x 4), so <em>3/4 </em>should get us 6 × 3 = 18.

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Marina drove 288 miles in the same amount of time it took Jaime to drive 312 miles. If Jaime drove 6 miles per hour faster than
sp2606 [1]

Let X = Marinas speed in MPH

Let T = Time

T=288/X
 312=(X+6)T
312=(X+6)(288/X)
312=288X/X+1728/X
312=288+1728/X
312-288=1728/X
24=1728/X
24X=1728

X=1728/24
X=72 MPH  FOR MARINA


 72+6=78 MPH FOR JAMIE


6 0
3 years ago
Un granjero tiene 100 vacas que pesan 125 kg cada una. El costo diario de mantenimiento de una vaca asciende a $ 5.00. Las vacas
solniwko [45]

Answer:

25 days

Step-by-step explanation:

Assuming that the farmer waits for n days to get get the maximum profit.

Given that the total number of cows the farmer has, = 100

Currect weight of one cow = 125 kg.

Weight gain rate for one cow = 3 kg/day

So, weight gained by one cow in n days = 3n kg

Therefore, the weight of one cow after n days = 125 + 3n \;\;kg \cdots(i)

Cost for keeping one cow = $5/day.

Cost for keeping one cow for n days = $ 5n

So, Cost for keeping 100 cows for n days = \$ 5n \times 100 =\$500n \cdots(ii)

Current market price = 25 pesos / kg = 125 cents / kg [ as 1 peso = 5 cents]

The falling rate of market price = 1 cent /day.

Fall in price in n days = 1\times n = n cents.

So, market price after n days = 125-n cent/kg\cdots(iii)

By using equations (i) and (iii),

The selling price of one cow after n days = (125+3n) \times (125-n) cents.

So, the selling price of 100 cows after n days = (125+3n) \times (125-n)\times 100 cents.

As 1 $ = 100 cents. so

The selling price of 100 cows after n days =\$ 5(125+3n) (125-n)\cdots(iv).

Now, from equations (ii) and (iv)

Net profit, P = 5(125+3n) (125-n) - 500n\cdots(v)

To get the maximum profit, differentiate the profit function in equation (v) with respect to n and equate it to zero to get the value of n, i.e

\frac {dP}{dn}=0 \\\\\Rightarrow \frac {d}{dn}(5(125+3n) (125-n) - 500n)=0 \\\\\Rightarrow  5[ (125+3n)(-1)+(125-n)(3)]-500=0 \\\\\Rightarrow 5[ -125-3n+375-3n]-500 =0 \\\\\Rightarrow 5[ -125-3n+375-3n]=500\\\\\Rightarrow 250-6n=500/5=100 \\\\\Rightarrow 6n = 250-100=150 \\\\\Rightarrow n= 150/6 = 25.

Hence, the farmer has to wait for 25 days to get the maximum profit.

3 0
3 years ago
Please help with 17 and 19
fomenos

Answer:

soory to say but you can search

5 0
3 years ago
Use completing the square to transform this equation into vertex form. Please state the coordinate of the vertex. X^2-8x-19=0
drek231 [11]

Answer:

(4 , - 35)

Step-by-step explanation:

X²-8x-19 =(x-4)² -35

y = a (x-h)² + k    a=1   , (h , k) -> (4 , - 35)

6 0
3 years ago
Katie has a 75% chance of making an A on a test. What is the probability that she will not make an A on her next two test: Algeb
andreev551 [17]
I am pretty sure it's B 6.25% but I'm not exactly sure
5 0
3 years ago
Read 2 more answers
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