N+d=47
5n+10d=295
divide 2nd by 5
n+2d=59
we have
n+d=47
n+2d=59
eliminate n
multiply first equaton by -1 and add to other equaton
-n-d=-47
<u>n+2d=59 +</u>
0n+1d=12
d=12
sub back
n+d=47
n+12=47
minus 12 both sides
n=35
35 nickles
D is answer
Answer:
D
Step-by-step explanation:
by looking at the point you can see what has a slope.
it is also a decreasing slope
Answer:
92398721
Step-by-step explanation:
Answer:
0.3902
Step-by-step explanation:
The question meets the criteria for the calculation of the confidence interval of a one sample proportion ;
Sample size, n = 27
Number of students with faster reaction time = 14
Phat = x / n = 14 / 27 = 0.6296
The confidence interval is calculated thus :
C. I = Phat ± Zcritical * √[p(1 - p)/n]
Zcritical at 99% = 2.576
C. I = 0.6296 ± 2.576 * √[0.6296(0.3704)/27]
C.I = 0.6296 ± 0.2394042
The lower boundary of C.I = 0.6296 - 0.2394042
Lower boundary = 0.3902
All you have to do is divide 92 by 6 and you get your answer. The remainder is the spaces she'll have left
