Question 1
2 answers:
You might be interested in
Answer:
Vanessa records a total of <u>11</u> quiz scores
Moe records a total of <u>10</u> quiz scores
According to the data, Vanessa's mean score is 80
According to the data, Vanessa's median score is 85
The range of Moe's quiz score is 45
The interquartile range of Moe's quiz score is 16.25
Step-by-step explanation:
Vanessa's score is given in the dot plot
Moe's scores are; 75, 80, 90, 90, 95, 55, 100, 95, 85, 85
1) The number of quiz scores Vanessa records is given by the number of dots on the dot plot, n = 11 dots ≡ 11 quiz scores
2) The number of quiz scores Moe records is given by the number of data points, n = 10 data points ≡ 10 quiz scores
3) Vanessa's mean score = ∑x/n
∑x/n = (60 + 2× 65 + 75 + 4 × 85 + 2 × 90 +95)/11 = 80
Vanessa's mean score = 80
4) Vanessa's median score is the (11 + 1)/2 th score = Her 6th score = 85
Vanessa's median score = 85
5) The range of Moe's score = Her largest score - Her least score = 100 - 55 = 45
The range of Moe's score = 45
6) Sorting Moe's scores gives;
75, 80, 90, 90, 95, 55, 100, 95, 85, 85
55, 75, 80, 85, 85, 90, 90, 95, 95, 100
The first quartile, Q₁ = 11/4th score = 2.75th score = 75 + 0.75 × 5 = 78.75
The 3rd quartile, Q₃ = The 3/4×11 score = 8.25th score = 95 + 0.25 ×0 = 95
The interquartile range, I = Q₃ - Q₁ = 95 - 78.75 = 16.25
The interquartile range of Moe's quiz score = 16.25.
Answer : The amount of margarine needed is 1 kg.
Step-by-step explanation :
First we have to convert volume of syrup from mL to L.
Conversion used:
1 L = 1000 mL
or, 1 mL = 0.001 L
So, 225 mL = 0.225 L
Now we have to calculate the amount of margarine needed.
As, 0.225 L of syrup needed 150 g of margarine
So, 1.8 L of syrup needed of margarine
Amount of margarine needed = 1000 g = 1 kg (1 kg = 1000 g)
Therefore, the amount of margarine needed is 1 kg.