Rewrite the following expression using the properties of logarithms. log2z+2log2x+4log9y+12log9x−2log2y

1 answer:

kramer3 years ago

5 0

Use the rules of logarithm:
1. log(x)+log(y)=log(xy)
log(x)-log(y)=log(x/y)
2. k*log(x) = log(x^k)
log(x)/k = log(x^(1/k))

log(2z)+2log(2x)+4log(9y)+12log(9x)−2log(2y)
=log(2z)+log(4x^2)+log(9^4y^4)+log(9^12x^12)−log(4y^2)
=log(2z)+log(4x^2)+log(6561y^4)+log(282429536481x^12)−log(4y^2)
=log(59296646043258912 * x^14 * y^6 * z)

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What is 3x^2-2n-5=0 please help me!!!

expeople1 [14]

The answer to your question is:
It is a quadratic equation in 'x', with 'n' mistakenly typed in the second term..

Although you didn't ask for the solutions to the equation, I'm already here
so I might as well go through it and find them:

3x² - 2x - 5 = 0

In terms of the generic quadratic formula:
A = 3
B = -2
C = -5

Plug those into the quadratic formula, and you discover that

x = -1
and
x = ⁵/₃

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rodikova [14]

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