All categories

3 years ago

Find the price of one candy bar if ten candy bars cost $40

Mathematics

2 answers:

zhuklara [117]3 years ago

6 0

$4•10=40
So they are all $4 apiece or you could go by doing this
40÷10=$4

likoan [24]3 years ago

6 0

In my opinion I think 4 times 10 which gives you 40 you basically get your answer!

You might be interested in

I need help I am stuck on this question and I'm not sure if this is the answer.

ioda

Answer:

62.8 in

Step-by-step explanation:

You have correctly filled appropriate values into the formula. However, your math failed to include the factor of 2.

C = 2πr = 2(3.14)(10 in) = 62.8 in

5 0

3 years ago

PART 1

Harrizon [31]

Answer:

Step-by-step explanation:

Part 1 is B and part 2 is A

5 0

3 years ago

IM TIMED HALP!!!

Fiesta28 [93]

Answer:

The table representing Relationship B is option 2

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}$

Step-by-step explanation:

The relationship shown by Relationship A and Relationship B = The change in the temperature for a pot of water om the stove

The rate of Relationship B > The rate of Relationship A

The table for relationship A is given as follows';

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&61.3\\3&&64.9\\7&&79.3\\9&&86.5\end{array}$

The time in minutes are the x-values, while the temperature in °C Ere the y-values

The rate for Relationship A, $m_A$ = (86.5 - 61.3)/(9 - 2) = 3.6

Therefore, the rate for Relationship B > 3.6

By checking each option, we note that in option 2, the maximum value for the y-value is the same as for Relationship A, which is 86.5°C, while the minimum value for the time, t, is lesser than that for Relationship A, (60.6 minutes < 61.3 minutes) therefore, we get;

The rate for option 2 = (86.5 - 60.6)/(9 - 2) = 3.7

Therefore, the table that represents the Relationship B is the table for option 2

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}$

5 0

3 years ago

The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of

Ivenika [448]

Maximum area of the rectangle is $9cm^{2}$

Explanation:

Considering the dimensions to be in cm

$f(x) = -(x-3)^{2} +9\\f(x) = -(x^{2} +9 - 6x)+9\\f(x) = -x^{2} +6x\\f'(x) = -2x+6\\-2x+6 = 0\\2x=6\\x=3cm\\\\$

Putting the value of x = 3

$Perimeter = 2(x+b)\\12 = 2(3+b)\\6 = 3+b\\b= 3cm$

$Area of rectangle = x X b\\ = 3 X 3\\ = 9cm^{2}$

Therefore, maximum area of the rectangle is $9cm^{2}$

7 0

3 years ago

A study was conducted to investigate whether a new drug could significantly reduce pan in people with arthritis. From a group of

Alinara [238K]

Answer:

d. Yes. All conditions for inference have been met.

Step-by-step explanation:

A study was conducted to investigate the effectiveness of a new drug whether it could significantly reduce pan in people with arthritis.

From a group of 500 people with arthritis 250 were randomly assigned to receive the drug (group 1) and the remaining people were assigned a placebo (group 2).

It is given that the people in the study were selected randomly.

The pooled proportion is given by

Pe = no. of people who reported pain relief in both groups/total number of people

Pe = (225 + 150)/500

Pe = 375/500

Pe = 0.75

Now let us check the condition np ≥ 10

250*0.75

187.5 ≥ 10

Satisfied

Now let us check the condition n(1 - p) ≥ 10

250(1 - 0.75)

250*0.25

62.5 > 10

Satisfied

Therefore, all conditions for inference have been met option d is the correct option.

5 0

3 years ago