Question

IM TIMED HALP!!!

Answer 1

Answer:

The table representing Relationship B is option 2

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}$

Step-by-step explanation:

The relationship shown by Relationship A and Relationship B = The change in the temperature for a pot of water om the stove

The rate of Relationship B > The  rate of Relationship A

The table for relationship A is given as follows';

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&61.3\\3&&64.9\\7&&79.3\\9&&86.5\end{array}$

The time in minutes are the x-values, while the temperature in °C Ere the y-values

The rate for Relationship A, $m_A$ = (86.5 - 61.3)/(9 - 2) = 3.6

Therefore, the rate for Relationship B > 3.6

By checking each option, we note that in option 2, the maximum value for the y-value is the same as for Relationship A, which is 86.5°C, while the minimum value for the time, t, is lesser than that for Relationship A, (60.6 minutes < 61.3 minutes) therefore, we get;

The rate for option 2 = (86.5 - 60.6)/(9 - 2) = 3.7

Therefore, the table that represents the Relationship B is the table for option 2

$\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}$