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3 years ago

What's .09 divided by 00.4806

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

You started out correctly, by moving the decimal of the divisor two places to the right so that it is a whole number (9). However, because the dividend is still a decimal after moving the decimal two places to the right, you "ignore" the decimal for now and divide 4806 by 9 which results in 534 and no remainder. You then "add" the decimal back to the quotient (534) by starting at the right and moving the decimal four places to the left because that is where the decimal was originally in 00.4806, which results in 0.0534, your final answer.

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Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

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4 0

3 years ago

The angle of depression from a helicopter to a landing pad is 37 degrees. if the helicopter is 1250 feet from the ground. what i

djyliett [7]

The horizontal distance from the helicopter to the landing pad is 1658.81 feet

<em><u>Solution:</u></em>

The figure is attached below

Triangle ABC is a rightangled triangle

A helicopter is flying at point A and landing pad is at point c

Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees

The helicopter is 1250 feet from the ground

Therefore, AB = 1250 feet

To find: horizontal distance from the helicopter to the landing pad

BC is the horizontal distance from the helicopter to the landing pad

BC = ?

By the definition of tan,

$tan \theta = \frac{opposite}{adjacent}$

$tan 37 = \frac{AB}{BC}\\\\tan 37 = \frac{1250}{BC}\\\\ 0.75355 = \frac{1250}{BC}\\\\BC = \frac{1250}{0.75355}\\\\BC = 1658.81$

Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet

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3 years ago