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PIT_PIT [208]
2 years ago
9

Can someone help me with the first 3 as it is my first time doing it ? I need help

Mathematics
1 answer:
Fed [463]2 years ago
7 0

You problem is you don't have any problem. You have a bunch of formulas for the perimeter and area of some shapes.

As for using the formulas, usually you're given all but one of the variables and you can solve for the remaining one.

Notice how the triangle result doesn't have area as a function of a, b and c. That's called Heron's formula and is usually not taught to secondary school students. I don't like to teach it either because Archimedes' Theorem is so much better:

The sides a,b,c and area S of a triangle satisfy

16S^2 = (a+b+c)(-a+b+c)(a-b+c)(a+b-c) = 4a^2b^2-(c^2-a^2-b^2)^2 = (a^2+b^2+c^2)^2 - 2(a^4+b^4+c^4)

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4(2x + 3) ÷ 5y
ololo11 [35]

Step-by-step explanation:

We do the brackets first, following BODMAS rules

so, 4× 5x ÷ 5y = 1xy.

= 4 × 1xy

= 4xy.

I guess that's the answer.

Example Of:-

<u>Sum:</u>

<em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em>y</em>

<u>term:</u><u> </u>

<em>5x + 7 = 5x and 7 are terms. </em>

<u>product</u><u>:</u>

<em>2a × 3b </em>

<u>factor:</u><u> </u>

<em>always </em><em>remember</em><em>,</em><em> </em><em>a </em><em>number </em><em>is </em><em>a </em><em>factor </em><em>of </em><em>itself.</em>

<em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em>y</em>

<em>factors </em><em>=</em><em> </em><em> </em><em>5</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>+</em><em> </em><em>y </em><em>+</em><em> </em><em>7</em><em>y</em><em>.</em>

<u>Quotient:</u><u> </u>

<em> </em><em>1</em><em>0</em><em>d</em><em> </em><em>÷</em><em> </em><em>5</em><em>j</em><em> </em><em>=</em><em> </em><em>2</em><em>d</em><em>j</em><em> </em>

<u>coefficient</u><u>:</u><u> </u>

<em>In the number 3x, </em><em>3</em><em> </em><em>is </em><em>the </em><em>coefficient</em><em> </em><em>of </em><em>x.</em><em> </em>

<em>but,</em><em> </em><em>in </em><em>the </em><em>number </em><em>x </em><em>(</em><em>raise </em><em>to)</em><em> </em><em>2</em><em>,</em><em> </em><em>the </em><em>coefficient</em><em> </em><em>is </em><em>1</em><em>.</em><em> </em>

<em>hope \: it \: helps \: you</em>

<h3 />

6 0
1 year ago
To estimate a population mean, the sample size needed to provide a margin of error of 3 or less with a 95% confidence when the p
Over [174]

Answer:

The minimum sample needed to provide a margin of error of 3 or less is 52.

Step-by-step explanation:

The confidence interval for population mean (<em>μ</em>) is:

\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

The margin of error is:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

<u>Given:</u>

MOE = 3

<em>σ </em>= 11

The critical value for 95% confidence interval is: z_{\alpha /2}=1.96

**Use the <em>z</em>-table for critical values.

Compute the sample size (<em>n</em>) as follows:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=1.96\times \frac{11}{\sqrt{n}}\\n=(\frac{1.96\times11}{3} )^{2}\\=51.65\\\approx52

Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.

7 0
2 years ago
James m
nadezda [96]
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2 years ago
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Use the web to find a data file containing information of your interest (i.e. energy consumption, financialtime series, biomedic
belka [17]
Maybe harry knows the answer...? you should try asking him

5 0
3 years ago
How many repeating digits are in the smallest group of repeating digits in the decimal equivalent of 2/9
AVprozaik [17]

Answer:

The answer is A.

Step-by-step explanation:

First, divide two by nine. The result is the decimal zero point two repeating.

Second, the digit that repeats is two. So, since two is one digit, the answer is A.

8 0
3 years ago
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