Answer:
12,7
Step-by-step explanation:
use pathogaras theorem
c^2=a^2+b^2
Answer:
9.06
Step-by-step explanation:
C
The numbers on the left represent 10 times that number
The numbers on the right are added to the end of the number on the left so
3I1=31 and 4I8=48 and 3I 1 1 2= 31 31 32
The answer is 28 years
At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079
t = ?
12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)
Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
