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Natasha_Volkova [10]
3 years ago
11

What is Jamal weight in kilograms if he weighs 156 pounds? Round to the nearest 10th if necessary

Mathematics
1 answer:
TEA [102]3 years ago
3 0

Answer:

70.7604097 in kilograms rounded would be 70.8 kilograms

Step-by-step explanation

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Please help me solve this
damaskus [11]
N=8
x= -19

Let me know if you need to see how to solve it
8 0
3 years ago
A circular mirror is surrounded by a square metal frame. The radius of the mirror is 5x. The side length of the metal frame is 1
Aleks04 [339]

Answer:

-25x^{2} (\pi -9)

Step-by-step explanation:

The area of the metal frame is equal to the area of the square minus the area of the circle.

The area of the square is the side length squared:

(15x)^{2}

=225x^{2}

The area of the circle is \pi r^{2}, with r being the radius:

\pi (5x)^{2}

=\pi *25x^{2}

=25\pi x^{2}

Now find the area of the metal frame:

225x^{2} -25\pi x^{2}

25x^{2} (9-\pi )   Factor out the GCF, 25x^{2}

-25x^{2} (\pi -9)   Factor out a -1

5 0
3 years ago
Find the circumference of a circle with a diameter of 7 cm.
professor190 [17]

Answer:

3.14

Step-by-step explanation:

if you want the exact answer you can multiply 7 by the value of

, that is = 3.14

3 0
3 years ago
Read 2 more answers
What is the lowest whole number for hypotenuse c when using the formula <img src="https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E2%2Bb%5E
nata0808 [166]

9514 1404 393

Answer:

  0

Step-by-step explanation:

If a=b, you are asking for a whole number c such that ...

  c = √(a² +a²) = a√2

If 'a' is a whole number, the only whole numbers that satisfy this equation are ...

  c = 0 and a = 0.

  0 = 0×√2

The lowest whole number c such that c = √(a²+b²) and a=b=whole number is zero.

__

√2 is irrational, so there cannot be two non-zero whole numbers such that c/a=√2.

_____

<em>Additional comment</em>

If you allow 'a' to be irrational, then you can choose any value of 'c' that you like. Whole numbers begin at 0, so 0 is the lowest possible value of 'c'. If you don't like that one, you can choose c=1, which makes a=(√2)/2 ≈ 0.707, an irrational number. The problem statement here puts no restrictions on the values of 'a' and 'b'.

3 0
3 years ago
If f and t are both even functions, is the product ft even? If f and t are both odd functions, is ft odd? What if f is even and
Natali5045456 [20]

Answer:

(a) If f and t are both even functions, product ft is even.

(b) If f and t are both odd functions, product ft is even.

(c) If f is even and t is odd, product ft is odd.

Step-by-step explanation:

Even function: A function g(x) is called an even function if

g(-x)=g(x)

Odd function: A function g(x) is called an odd function if

g(-x)=-g(x)

(a)

Let f and t are both even functions, then

f(-x)=f(x)

t(-x)=t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=f(x)t(x)

ft(-x)=ft(x)

The function ft is even function.

(b)

Let f and t are both odd functions, then

f(-x)=-f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[-f(x)][-t(x)]

ft(-x)=ft(x)

The function ft is even function.

(c)

Let f is even and t odd function, then

f(-x)=f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[f(x)][-t(x)]

ft(-x)=-ft(x)

The function ft is odd function.

7 0
3 years ago
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