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kolbaska11 [484]
3 years ago
10

Select the statement that can be written as a TRUE biconditional. If two angles are adjacent, then they form a linear pair. If a

number is divisible by 2, then it is divisible by 4. If three points are collinear, then they lie on the same line. If B is between A and C, then AB = BC.

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Please refer to the attached figure.

Here, x and y are adjacent angles. However, they do not form a linear pair as the sum x + y < 180 degrees.

So, the first statement is FALSE.

Consider the number 6. It is divisible by 2 but it is not divisible by 4.

So, the second statement is FALSE

Three points are said to be collinear, if they lie on the same line.

So, the third statement is TRUE.

Please refer to the second figure attached.

Here, AB = 2 cm and BC = 7 cm.

So, however B is between A and C, AB ≠ BC.

So, the fourth statement is FALSE.

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Answer:

Reasons:

1. Given

2. Given

3. Definition of bisector

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Step-by-step explanation:

This is quite easy to solve. All that you're expected to do is to complete the reason that justifies each statement given in the two-column proof.

Let's complete the proof as follows:

1. Statement: DF \cong EF

1. Reason: Given

We know this statement is true because we are given in the question.

2. Statement: FG bisects <DFE

2. Reason: Given

We also know this because we are told so in the question, as shown in the diagram given.

3. Statement: \angle 1 \cong \angle 2

3. Reason: Definition of bisector

We know this because an angle bisector divides an angle into two equal halves. Therefore, the definition of bisector justifies why it was stated that \angle 1 \cong \angle 2

4. Statement: \overline{FG} \cong \overline{FG}

Reason: Reflexive property.

5. Statement: ∆DFG \cong EFG

5. Reason: SAS Congruence

Two sides (DF and FG) and an included angle (angle 1) of ∆DFG is congruent two corresponding sides (EF and FG) and an included angle (angle 2) of ∆EFG. Therefore, ∆DFG \cong EFG by the Side-Angle-Side (SAS) Congruence Theorem.

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