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hodyreva [135]
3 years ago
11

Complete the two-column proof using the answers in the bank. Given: DF ≅ EF FG bisects ∠DFE Prove: ∆DFG ≅∆EFG

Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

Reasons:

1. Given

2. Given

3. Definition of bisector

4. Reflexive property

5. SAS Congruence

Step-by-step explanation:

This is quite easy to solve. All that you're expected to do is to complete the reason that justifies each statement given in the two-column proof.

Let's complete the proof as follows:

1. Statement: DF \cong EF

1. Reason: Given

We know this statement is true because we are given in the question.

2. Statement: FG bisects <DFE

2. Reason: Given

We also know this because we are told so in the question, as shown in the diagram given.

3. Statement: \angle 1 \cong \angle 2

3. Reason: Definition of bisector

We know this because an angle bisector divides an angle into two equal halves. Therefore, the definition of bisector justifies why it was stated that \angle 1 \cong \angle 2

4. Statement: \overline{FG} \cong \overline{FG}

Reason: Reflexive property.

5. Statement: ∆DFG \cong EFG

5. Reason: SAS Congruence

Two sides (DF and FG) and an included angle (angle 1) of ∆DFG is congruent two corresponding sides (EF and FG) and an included angle (angle 2) of ∆EFG. Therefore, ∆DFG \cong EFG by the Side-Angle-Side (SAS) Congruence Theorem.

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Step-by-step explanation:

Based on the situation, it forms into a right triangle. So we will apply the Pythagorean Theorem here. The ladder acts as the hypotenuse while the height from the ground to the window serves as our side "a". We are tasked to solve for "b". Side "b" is the distance from foot of side a to the tip of side c which is the hypotenuse (ladder). We will derive the formula below to solve for b.

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