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hodyreva [135]
3 years ago
11

Complete the two-column proof using the answers in the bank. Given: DF ≅ EF FG bisects ∠DFE Prove: ∆DFG ≅∆EFG

Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

Reasons:

1. Given

2. Given

3. Definition of bisector

4. Reflexive property

5. SAS Congruence

Step-by-step explanation:

This is quite easy to solve. All that you're expected to do is to complete the reason that justifies each statement given in the two-column proof.

Let's complete the proof as follows:

1. Statement: DF \cong EF

1. Reason: Given

We know this statement is true because we are given in the question.

2. Statement: FG bisects <DFE

2. Reason: Given

We also know this because we are told so in the question, as shown in the diagram given.

3. Statement: \angle 1 \cong \angle 2

3. Reason: Definition of bisector

We know this because an angle bisector divides an angle into two equal halves. Therefore, the definition of bisector justifies why it was stated that \angle 1 \cong \angle 2

4. Statement: \overline{FG} \cong \overline{FG}

Reason: Reflexive property.

5. Statement: ∆DFG \cong EFG

5. Reason: SAS Congruence

Two sides (DF and FG) and an included angle (angle 1) of ∆DFG is congruent two corresponding sides (EF and FG) and an included angle (angle 2) of ∆EFG. Therefore, ∆DFG \cong EFG by the Side-Angle-Side (SAS) Congruence Theorem.

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Step-by-step explanation:

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