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2 years ago

Evaluate the algebraic expression 1.5t-7.2 for each given value.

Mathematics

2 answers:

svet-max [94.6K]2 years ago

8 0

Answer:

1.8 and -14.7

Step-by-step explanation:

Given the algebraic expression 1.5t-7.2, to get the value of the expression when t = 6, we will substitute the value of t in the given equation to have;

1.5(6)-7

= 9.0-7.2

= 1.8

Similarly when t = -5, the expression 1.5t-7.2 gives;

1.5(-5)-7.2

= -7.5-7.2

= -14.7

Therefore the expression of the equation at x = 6 is 1.5(6)-7.2 gives 1.8 will at x=-5 gives 1.5(-5)-7.2 which gives -14.7

erastovalidia [21]2 years ago

6 0

Answer:

1.8 and -14.7

Step-by-step explanation:

its just to substitute it as t and simplify

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Write an equation that has a slope of -2 and passes through (-6, 2)

Lelechka [254]

Answer:

y = - 2x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute (- 6, 2) into the partial equation

2 = 12 + c ⇒ c = 2 - 12 = - 10

y = - 2x - 10 ← equation of line

5 0

3 years ago

Expand.<br> (x^2)(x^2-6)

Liono4ka [1.6K]

Answer:

This can be expanded to x⁴ - 6x²

Step-by-step explanation:

$x^2(x^2 - 6)\\= x^4 - 6x^2$

5 0

2 years ago

Read 2 more answers

Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2

aliya0001 [1]

First we'll substitute $\frac{dy}{dx}$ with $y'$

$y'=\frac{4x}{y}$

Then we can separate this.

$yy'=4x$

Then we'll solve this.

$yy'=4x: \frac{y^2}{2}=2x^2+c_1$

$\frac{y^2}{2}=2x^2-6$

$y=2\sqrt{x^2-3},y=-2\sqrt{x^2-3}$

Then we'll plug in to find the extraneous solutions (if any)

$y=-2\sqrt{x^2-3}$

7 0

3 years ago

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0

3 years ago

The cost c, for manufacturing x flags is given by c=x? -24x +39. Find the number of flags manufactured if the cost is $120.

IRINA_888 [86]

9514 1404 393

Answer:

Step-by-step explanation:

You want to find x when c = 120.

120 = x^2 -24x +39

x^2 -24x -81 = 0 . . . . . . subtract 120 to put in standard form

(x -27)(x +3) = 0 . . . . . .factor it

Solutions are ...

x = 27, x = -3 . . . . . values of x that make the factors zero

The number of flags manufactured for a cost of $120 is 27 flags.

8 0

2 years ago