Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
Answer:
r = √98
Step-by-step explanation:
angle A and the diameter form an isosceles right triangle, with OA as the hypotenuse and r as the other sides. You can then make and solve an equation from the Pythagorean Theorem:
r^2 + r^2 = 14^2
2r^2 = 14^2
2r^2 = 196
r^2 = 98
r = √98
Answer:
23
Step-by-step explanation:
F=(9/5)c + 32
F=(9/5)(-5) + 32
F=(-9) + 32
F=23
Answer:
2.45, -2.45
Step-by-step explanation:
Since the equation has only one term in the unknown "x", we can solve for it isolating "x" on one side of the equal sign:

Which we can round to: x = - 2.45 and x = 2.45
Answer:
G. 
Step-by-step explanation: