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prisoha [69]
3 years ago
12

You roll a six-sided die twice. What is the probability of rolling a 2 and then an odd number?​

Mathematics
2 answers:
shusha [124]3 years ago
5 0

Answer:

1/12

Step-by-step explanation:

possible outcome for a die = 6

Probability of rolling a 2 P(2) = 1/6

probability of rolling a odd number = no of odd numbers/ total possible outcome

P(odd) = 3/6 =1/2

probability of rolling a 2 and then an odd number = 1/6 x 1/2 = 1/12

Oduvanchick [21]3 years ago
3 0

Answer:

1/3

Step-by-step explanation:

What is the probability of rolling a 2 and then an odd number?​

1, 2, 3, 5

4/12 bc u are rolling it twice

4/12 divided by 4 = 1/3

hope im correct and hope i helped

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8 0
3 years ago
Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

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4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

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4×3 (3^2)^2 x^6 y^14 x^10 y^10

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4×3×9^2 x^6 y^14 x^10 y^10

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4×3×81 x^6 y^14 x^10 y^10

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4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

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Answer: 972 x^16 y^24

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Answer:

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Step-by-step explanation:

1. Let's calculate the probability of spinning an odd number:

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2. Let's calculate the probability of getting tails on the coin:

We can toss a coin and get tails one out of 2 events, it means that the probability of getting tails on the coin is:

1/2

3. These are independent events because the fact that we spin an odd number does not affect the probability of getting tails on the coin, thus:

Probability of spinning an odd number  and getting tails on the coin =

3/5 * 1/2 = 3/10

<u>The correct answer is B. 3/10</u>

5 0
3 years ago
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