From the solution of the expression, it can be seen that s = 6 when t = 3 while t = 1 when s = 2.
<h3>How do we solve a mathematical expression?</h3>
Given:
(12t) = (6s) ........................ (1)
When t = 3, we can solve for s from the expression in equation (1) by substituting t = 3 into the equation as follows:
12 * 3 = 6s
36 = 6s
s = 36 / 6
s = 6
When s = 2, we can solve for t from the expression in equation (1) by substituting s = 2 into the equation as follows:
12t = 6 * 2
12t = 12
t = 12 / 12
t = 1
Learn more about mathematical expression here: brainly.com/question/12401681.
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Answer:
k = 4
Step-by-step explanation:
3k - 2 = 10
3k - 2 + 2 = 10 + 2 (adding 2 to both sides)
3k = 12
3k/3 = 12/3 (dividing both sides by 3)
k = 4
Happy to help :)
Answer:
(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x - 7
y = -x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x - 7 = -x + 5
- [Addition Property of Equality] Isolate <em>x</em> terms: 3x - 7 = 5
- [Addition Property of Equality] Isolate <em>x</em> term: 3x = 12
- [Division Property of Equality] Isolate <em>x</em>: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -x + 5
- Substitute in <em>x</em>: y = -4 + 5
- Add: y = 1
Answer:
(8,5)
Step-by-step explanation:
5x-2y=30
lets substitute "8" as x and see where that takes us
5(8)-2y=30
40-2y=30
subtract 40 on both sides
-2y=-10
divide by "-2" on both sides
y=5
(8,5) is your answer
