You would have to calculate the percent first.
Add the total number of students
3420+4680= 8100 students TOTAL
Then you would divide the amount of students by the total
3420 part time/8100 students total = .42 or 42%
4680 full time/8100 total = .58 or 58%
Then you multiply the percentages by 90
(90)(.58)= 52.2
(90)(.42)= 37.8
Rounded
52 full time and 38 part time students
Answer: b = p - a -c
Step-by-step explanation:
p= a + b + c Solving for b means getting b on one side by itself.
p = a + b + c To solve for b first subtract a from both sides to get,
-b -b
p - a = b + c Now subtract c from both sides to get
-c -c
p - a - c = b
b = p - a -c
So the answer would be A. I had a bit of trouble figuring this out, but then I went to Order of Operations and found it out.
So you fill in n, and I just used 9 since it's in the question. So then, subtract 1 from 9, giving you 8. Then you multiply 0.35 by 8, giving you 2.8. Now lastly, add 7.51, and you get 10.31
I hope this helps you! If it does, please rate as Brainliest :D
Answer:
Step-by-step explanation: X=2
Answer:
38.89% probability that a student that is taking Physics is also taking Statistics
Step-by-step explanation:
Conditional probability formula:
Two events, A and B.
In which
P(B|A) is the probability of B happening, given that A has happened.
is the probability of these two events happening.
P(A) is the probability of A happening.
In this problem, we have that:
A: physics
B: statistics.
90% of the students take Physics
This means that 
35% of the students take both Physics and Statistics.
This means that 
So
38.89% probability that a student that is taking Physics is also taking Statistics
