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Anvisha [2.4K]
3 years ago
13

Express 1)32.12353535... 2)2.3333...+4.15151515... as a fraction in simplest form

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

(1) Suppose <em>x</em> = 32.12353535... . Then 100<em>x</em> = 3212.353535... and 10000<em>x</em> = 321235.353535... .

Subtracting these gives

10000<em>x</em> - 100<em>x</em> = 321235.353535... - 3212.353535...

9900<em>x</em> = 321235 - 3212

9900<em>x</em> = 318023

<em>x</em> = 318023/9900

(2) By the same process as above, we start with

<em>x</em> = 2.333...

<em>y</em> = 4.151515...

Then

10<em>x</em> = 23.333...

==>  10<em>x</em> - <em>x</em> = 23.333... - 2.333...

==>  9<em>x</em> = 23 - 2

==>  <em>x</em> = 21/9

and

100<em>y</em> = 415.151515...

==>  100<em>y</em> - <em>y</em> = 415.151515... - 4.151515

==>  99<em>y</em> = 415 - 4

==>  <em>y</em> = 411/99

After this, we get

<em>x</em> + <em>y</em> = 2.333... + 4.151515...

==>  <em>x</em> + <em>y</em> = 21/9 + 411/99

==>  <em>x</em> + <em>y</em> = 231/99 + 411/99

==>  <em>x</em> + <em>y</em> = 642/99 = 214/33

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