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DiKsa [7]
3 years ago
5

Show that 5/6 - 3/4 = 1/12

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0
<u>5</u> x2 - <u>3</u> x2 = <u>10</u> - <u>9 </u>= <u>  1</u>
6 x2    4 x2    12  12  12
Hope it helps!
spayn [35]3 years ago
4 0
We have to check if LHS = RHS
First solve LHS
\frac{5}{6}- \frac{3}{4} = \frac{5*2}{6*2}- \frac{3*3}{4*3} = \frac{10}{12}- \frac{9}{12}= \frac{1}{12}&#10;So LHS is equal to RHS.
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Which of the following is a polynomial with rootsnegative square root of 5, square root of 5, and 3
Scrat [10]

Answer:

P(x) = x³ - 3x² - 5x + 15

Step-by-step explanation:

∵ The roots of the polynomial are -√5 , √5 , 3

∴ The polynomial has 3 factors:

  (x - √5) , (x + √5) , (x - 3)

∴ P(x) = (x - √5)(x + √5)(x - 3)

          = (x² + √5x - √5x - 5)(x - 3)

          = (x² - 5)(x - 3) = x³ - 3x² - 5x + 15

∴ P(x) = x³ - 3x² - 5x + 15

3 0
2 years ago
4) You randomly select one card from a​ 52-card deck. Find the probability of selecting the 6 of hearts or the ace of diamonds.
MakcuM [25]

Answer:

1/26

Step-by-step explanation:

There is only one 6 of hearts and only one ace of diamonds.

The probability of selecting the 6 of hearts is thus 1/52, and that of selecting the ace of diamonds is also 1/52.

The probability of selecting the 6 of hearts or the ace of diamonds is the SUM of these two results:  1/52 + 1/52 = 2/52 = 1/26.

8 0
2 years ago
Read 2 more answers
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blagie [28]

Answer:

Step-by-step explanation:

5 0
3 years ago
A service attendant is paid time and a 1/2 for working over 40 hours per week last week. The attendant work 47 hours and earned
devlian [24]
Write and solve an equation:

Total earnings = $782.75 = s(40 hrs) + 1.5*s*(7 hrs)

Then 782.75 = 40s + 10.5s = 50.5s

Dividing both sides by 50.5:  s = 15.5.  The attendant's regular hourly wage was $15.50.
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3 years ago
Theorem: the sum of any two even integers equals 4k for some integer k. "proof: suppose m and n are any two even integers. by de
icang [17]

Remark

The proof is only true if m and n are equal. Make it more general.

m = 2k

n = 2v

m + n = 2k + 2v = 2(k + v).

k and v can be equal but many times they are not. From that simple equation you cannot do anything for sure but divide by 2.

There are 4 combinations

m is divisible by 4 and n is not. The result will not be divisible by 4.

m is not divisible by 4 but n is. The result will not be divisible by 4.

But are divisible by 4 then the sum will be as well. Here's the really odd result

If both are even and not divisible by 4 then their sum is divisible by 4

3 0
3 years ago
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