Using it's concept, it is found that the sample proportion for this population is of 0.4.
- The estimate of the <em>sample proportion for a population</em> is given by the <u>number of desired outcomes divided by the size of the sample</u>.
In this problem:
- 1,599 of those surveyed responded in favor of the park.
- The sample size is of 4,000.
Hence:
The sample proportion for this population is of 0.4.
A similar problem is given at brainly.com/question/14510808
<em>Hope it helps and is useful :)</em>
Answer:
General Solution is 
and the particular solution is 
Step-by-step explanation:
This is a linear diffrential equation of type
..................(i)
here 
The solution of equation i is given by
we have ![e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}](https://tex.z-dn.net/?f=e%5E%7B%5Cint%20p%28x%29dx%7D%3De%5E%7B%5Cint%20%5Cfrac%7B-2%7D%7Bx%7Ddx%7D%5C%5C%5C%5Ce%5E%7B%5Cint%20%5Cfrac%7B-2%7D%7Bx%7Ddx%7D%3De%5E%7B-2ln%28x%29%7D%5C%5C%5C%5C%3De%5E%7Bln%28x%5E%7B-2%7D%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%5C%5C%5C%5C%5Cbecause%20e%5E%7Bln%28f%28x%29%29%7D%3Df%28x%29%5D%5C%5C%5C%5CThus%5C%5C%5C%5Ce%5E%7B%5Cint%20p%28x%29dx%7D%3D%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%7D)
Thus the solution becomes
This is the general solution now to find the particular solution we put value of x=2 for which y=6
we have 
Thus solving for c we get c = -1/2
Thus particular solution becomes
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
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Answer:
5% but not sure
Step-by-step explanation:
80+5+10
