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Stels [109]
2 years ago
13

Suppose you order a pizza with a diameter of

Mathematics
1 answer:
Valentin [98]2 years ago
3 0

Answer: 9

Step-by-step explanation: if the diameter of the pizza is 18 inches then the radius would be half of that, 9.

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What is the slope of the line passing through the points (−3, 4) and (4, −1)?
Igoryamba
Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is 
m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The two given points are (-3,4) and (4,-1). Therefore the slope is
m= \frac{-1-4}{4-(-3)} = \frac{-5}{7}

Answer: - \frac{5}{7}

3 0
3 years ago
A circle has an area of 78.5 square inches what is the radius of the circle
Alinara [238K]

Answer:

Step-by-step explanation:

Area of circle = 78.5 in²

πr² = 78.5

3.14*r² = 78.5

r^{2}=\frac{78.5}{3.14}\\\\=\frac{78.5*100}{3.14*100}\\\\=\frac{7850}{314}\\\\r^{2}=25\\r=\sqrt{25}=\sqrt{5*5}\\\\

r =  5 in

3 0
2 years ago
Read 2 more answers
Help Por favor! Will mark brainliest!
postnew [5]

Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.

Step-by-step explanation:

1). 2x + 3y = 33

2). 5x + 2y = 55

3). I’m going to use substitution.

Isolate a variable (x):

2x + 3y = 33

2x = -3y + 33

X = (-3y + 33)/2

X = -3/2y + 33/2

Substitute and solve for y:

5x + 2y = 55

5(-3/2y + 33/2) + 2y = 55

-15/2y + 165/2 + 2y = 55

-11/2y = -55/2

Y = 5 <— children’s ticket.

Solve for x:

2x + 3y = 33

2x + 3(5) = 33

2x + 15 = 33

2x = 18

X = 9 <— adult’s ticket.

Check:

5x + 2y = 55

5(9) + 2(5) = 55

45 + 10 = 55

55 = 55

2x + 3y = 33

2(9) + 3(5) = 33

18 + 15 = 33

33 = 33

8 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
The number of books sold over the course of the four-day book fair were 190, 100, 272, and 74. Assume that samples of size 2 are
g100num [7]

Answer:

the answer is below

Step-by-step explanation:

We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)

in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean

x1 x2 probabilityP(x1,x2) sample mean

190 190    1/16                 190

190 100    1/16                 145

190 272    1/16                 231

190 74    1/16                 132

100 190    1/16                 145

100 100    1/16                 100

100 272    1/16                 186

100 74    1/16                        87

272 190    1/16                 231

272 100    1/16                 186

272 272    1/16                 272

272 74    1/16                 173

74 190    1/16                 132

74 100    1/16                 87

74 272    1/16                 173

74 74    1/16                 74

Summarizing above with adding duplicate values

sample mean   probability

       74              1/16

      87               1/8

    100                1/16

    132                1/8

    145                1/8

    173                1/8

   186                1/8

   190               1/16

    231               1/8

   272               1/16

5 0
3 years ago
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