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Charra [1.4K]
3 years ago
7

Hey can you please help me posted picture of question

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
The correct answer is option B.

Solution is shown below

y= 4 x^{3} \\  \\ 
 \frac{y}{4} = x^{3}  \\  \\ 
 \sqrt[3]{\frac{y}{4}}  =x \\  \\ 
f^{-1}(y)= \sqrt[3]{\frac{y}{4}} \\  \\ 
f^{-1}(x)= \sqrt[3]{\frac{x}{4}} \\  \\ 
y^{-1}= \sqrt[3]{\frac{x}{4}}
natima [27]3 years ago
3 0
The correct answer is B
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Answer:

The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.

Step-by-step explanation:

Sample size of 30 or larger, so we can use the normal distribution to find the confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

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The upper end of the interval is the sample mean added to M. So it is 71492 + 8 = 71500 km.

The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.

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