Question

Hey can you please help me posted picture of question

Answer 1

The correct answer is option B.

Solution is shown below

$y= 4 x^{3} \\ \\ \frac{y}{4} = x^{3} \\ \\ \sqrt[3]{\frac{y}{4}} =x \\ \\ f^{-1}(y)= \sqrt[3]{\frac{y}{4}} \\ \\ f^{-1}(x)= \sqrt[3]{\frac{x}{4}} \\ \\ y^{-1}= \sqrt[3]{\frac{x}{4}}$

Answer 2

The correct answer is B