For this case we have the following definitions:
A function is even if, for each x in the domain of f, f (- x) = f (x). The even functions have reflective symmetry through the y-axis.
A function is odd if, for each x in the domain of f, f (- x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.
We then have the following function:
Applying the definitions we have:
Answer:
The function is not odd because it is fulfilled:
Therefore, the function is even.
no because it is not a right angled triangle.
this means angle A is not 90° so AB cant be a tangent.
Answer:
the scale factor and the ratio of their perimeters is 8/9
Step-by-step explanation:
k^2=area 1/area 2
k^2=64/81
=square root if k^2=square root of 64/81
=<u>k</u><u>=</u><u>8</u><u>/</u><u>9</u>
S is 27. SRT is 63 becuase of the vertical angles theorem. All angles of a triangle add up to 180, and you already have the other two angles. So its 27
Answer:
x=20
Step-by-step explanation:
Rewrite the equation as
x
/32
=
5/
8
Multiply both sides of the equation by 32
32 ⋅ x /32 = 32 ⋅ 5/8
Simplify both sides of the equation.
Cancel the common factor of
32
Cancel the common factor.
<h3><u>
32·</u> x/<u>32</u> · 5/8
</h3>
Rewrite the expression.
x = 32 ⋅ 5/8
Simplify
32⋅5/8
Cancel the common factor of
8
Factor 8 out of 32
x = 8 ( 4 ) ⋅ 5/8
Cancel the common factor.
Rewrite the expression.
x = 4 ⋅ 5
Multiply 4 by 5
