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hodyreva [135]
3 years ago
13

The test statistic of z=1.92 is obtained when testing the claim that p≠0.767. a. Identify the hypothesis test as being​ two-tail

ed, left-tailed, or​ right-tailed. b. Find the​ P-value. c. Using a significance level of α=0.10​, should we reject H0 or should we fail to reject H0​?
Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

it is a two tailed test

The p - value for z=1.92  is 0.9726

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

Step-by-step explanation:

For p≠0.767

Taking  null hypothesis as p≠0.767 and alternate hypothesis as p =0.767

H0 :p≠0.767  Ha :p≠0.767  it is a two tailed test

The p - value for z=1.92  is 0.9726 from the table.

Using a significance level of α=0.10

z value for 0.10 for two tailed test is ± 1.645

Z >zα

1.92> ± 1.645

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

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if you put it together you get 3n+1

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6 0
4 years ago
Read 2 more answers
Is this correct?
ioda
Um
first note that x=-7 is not allowed in the soltions set
multiply both sides by x+7
make a sign chart and input values and see what they are

ok so we know we have zeroes at x=-9 and x=11
and x=-7 is not allowed so

see attachment


at x=-10,, we get a negative sign so it is less than 0
at x=-8, we get a positive sing, so it is more than 0
at x=-3, we get a negative sign, so less than 0
at x=20, we get a positive sign,so greater

so then

we do from negative inity to -9
and not between -9 and -7
between -7 and 11
so then

(-infinity,-9)U(-7,11]

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