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vesna_86 [32]
3 years ago
7

A construction worker needs to put a rectangular window in the side of a building. He knows from measuring that the top and bott

om of the window have a width of 9 feet and the sides have a length of 12 feet. He also measured one diagonal to be 15 feet. What is the length of the other diagonal?

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer: 15 feet

Step-by-step explanation:

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What two nonnegative real numbers with a sum of 60 have the largest possible​ product?
kogti [31]
The biggest possible real number = 60 ÷ 2  = 30

30 + 30 = 60

Largest Product = 30 x 30 = 900

Answer: The two numbers are 30 and 30.
6 0
3 years ago
Solve for y: x=5y-3
kobusy [5.1K]
X=5y-3
-5y=-x-3
5y=x+3
y=x/5 + 3/5
7 0
3 years ago
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The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
1.your aswer:
lutik1710 [3]

Answer:

Tess is correct

Step-by-step explanation:

First off, to find out the new discounted price without the sales tax, you multiply $24.50 by 15% (0.15). This gives you $3.68. You then subtract the $3.68 from $24.50. You get $20.82. To find the total with sales tax you then multiply the $20.82 by 10% (0.1). You add the discounted price with the sales tax and get the conclusion that they have enough money for the book.

3 0
3 years ago
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Complete the square to solve the equation below. x^2-10x-2=17​
Naddika [18.5K]

Answer:

Exact form : x = +_2 squareroot 11+5

Decimal form : x=11.63324958...,-1.63324958...

Step-by-step explanation: Use the formula (b/2)^2 in order to create a new term. Solve for x by using the term to complete the square.

I hope this helps you out! :)

8 0
3 years ago
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