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3 years ago

28th term of -242, -251, -260

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

-485

Step-by-step explanation:

Formula

Givens

an = a28

n = 28

a1 = - 242

Solution

d = a3 - a2

d = -260 - - 251

d = -260 + 251

d = - 9

an = a1 + (n-1)d

an = -242 + (n - 1)(-9)

a28 = - 242 + 27*(-9)

a28 = - 242 - 243

a28 = - 485

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Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
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Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

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Step 3: Evaluate

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Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$