Answer:
Step-by-step explanation:
![if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) = {4}^{2} \\ f[g(4)] = 4( {4}^{2} ) + 2 \\ f[g(4)] = 4(16) + 2 \\ f[g(4)] =64 + 2 \\ f[g(4)] = \boxed{66}](https://tex.z-dn.net/?f=%20if%20%5C%3A%20the%20%5C%3A%20question%20%5C%3A%20is%20%5C%3A%20f%5Bg%284%29%5D%20%5C%5C%20then%20%5C%3A%20at%20%5C%3A%20first%20%5C%3A%20solve%20%5C%3A%20for%20%5C%3A%20g%284%29%20%5C%5C%20g%284%29%20%3D%20%20%7B4%7D%5E%7B2%7D%20%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%28%20%7B4%7D%5E%7B2%7D%20%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%2816%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D64%20%2B%202%20%5C%5C%20%20%20f%5Bg%284%29%5D%20%20%3D%20%20%5Cboxed%7B66%7D)
Answer:
7/1 - 7/1 + 17/1 = 17
Step-by-step explanation:
Answer:
The average number of trials required to get the first success
16/2 times 2 =16, 2/2 times 16 = 16
Answer:
(C)0.9, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.3
Step-by-step explanation:
In (A), (B), (D) and (E) options, all have similar set of numbers and ranges between 2 to 10. Moreover these contains the whole numbers, so when we find mode, median and mean of these data sets, they will follow the same path.
But in (C), the data values involves decimals and are not the part of the other data values and it goes from 0.9-1.3, thus making them farthest from a normal distribution when mean, mode and median are calculated.
Thus, option (C) is correct.
