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Korvikt [17]
3 years ago
15

Consider two events such that P(A)=1/4, P(B)=2/5, and P(A∩B)=1/10. Are events A and B independent events?

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0
Yes, they are independent. First of all, we know that P(A) = 1/4, P(B) = 2/5, and P(A and B) = 1/10. To know if two events are independent, the following questions must be true: P(A)*P(B) = P(A and B). So since (1/4)*(2/5) = 2/20 which equals 1/10, these events are independent
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Bob is buying coffee for his coffee machine.Option 1 is $5.99 for 12 coffeesOption 2 is 23.99 for 70 coffee Which is the better
velikii [3]

Step 1: Let's review the information provided to us to answer the problem correctly:

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• Option 2: $ 23.99 for 70 coffee

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6 0
1 year ago
Can someone please help me out<br> ASAP I WILL GIVE OUT BRAINLY
SashulF [63]

Answer:

x = 9

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Step-by-step explanation:

First, find x. to do so, set your formula up as

18 = 8x - 54

18 + 54 = 8x

72 = 8x

72/8 = x

9 = x

Now that you have x, find your missing side

2x + 1 = y, x

2 * 9 + = y

19 = y

Your perimeter is P = 2(l+W)

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3 0
3 years ago
Read 2 more answers
What is the total after a 10% discount of 346.10
AVprozaik [17]
It is 311.49. You would multiply 0.10 and 349.10, which is 34.61. Then subtract 34.61 from 349.10, which is 311.49. So, after a 10% discount of 346.10, the answer would be 311.49
5 0
3 years ago
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