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3 years ago

Consider two events such that P(A)=1/4, P(B)=2/5, and P(A∩B)=1/10. Are events A and B independent events?

1 answer:

3 0

Yes, they are independent. First of all, we know that P(A) = 1/4, P(B) = 2/5, and P(A and B) = 1/10. To know if two events are independent, the following questions must be true: P(A)*P(B) = P(A and B). So since (1/4)*(2/5) = 2/20 which equals 1/10, these events are independent

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3(12-3y^2) Help solve this please

HACTEHA [7]

Step 1. Distribute

 $3*12+3*-3 y^{2}$

Step 2. Simplify $3*12$ to $36$

$36+3*-3 y^{2}$

Step 3. Simplify $3*-3 y^{2}$ to $-9 y^{2}$

$36-9 y^{2}$

Done! :)

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3 years ago

PLEASE HELP 2. If f(x) = 3x2 – 7x + 2, then f(- 1) = ? (A) 18 B. 12 C.-2 D.-8.

makvit [3.9K]

Answer: B. 12

Step-by-step explanation:

f(x) = 3x2 – 7x + 2

f(- 1) = ?

f(-1)=3(-1)^2-7(-1)+2

=3(1)+7+2

=3+7+2

=12

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2 years ago

I have a series of questions

alexgriva [62]

9514 1404 393

Answer:

0.4, 0.004, 0.004

Step-by-step explanation:

The "what" in each case is found by dividing the target value by 10. That is accomplished by moving the decimal point one place to the left.

4/10 = 0.4 ⇒ 10 times 0.4 = 4

0.04 and .04 are exactly the same value, so the last two on your list are the same:

0.04/10 = 0.004 ⇒ 10 times .004 = 0.04

3 0

3 years ago

Haley is twice as old as Riley. The sum of their ages is 39. Write an equation that represents (x) , Riley's age.

kenny6666 [7]

Answer:

X=39×2. Answer: 39×2= 78

6 0

3 years ago

Read 2 more answers

Find a polynomial of degree 3 with real cofficients and zeros of -3,-1,4 for which f(-2)=24

konstantin123 [22]

$\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0$

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

$\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y$

darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.

$\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill$

4 0

3 years ago