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givi [52]
3 years ago
13

A tennis player wins a match 55% of the time when she serves first and 47% of the time when her opponent serves first. The playe

r who serves first is determined by a coin toss before the match. What is the probability that the player wins a given match?
Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0

ok so she has a 50% chance of serving first so if she serves first she has a 55% percent chance of winning multiply .55 and .50 to get .275 now she also has a 50% chance of not serving first so multiply .47 and .50 to get .235 now that you have the two probabilities of her winning you add them together so .275+.235 = .51 so she has a <u>51%</u> chance of winning the game
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Fynjy0 [20]

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

6 0
3 years ago
Read 2 more answers
F(x)= x squared -3x + 2 divided by 3x squared + 9 x -12
VashaNatasha [74]

Answer:

=(x-2)/3(x+4)

Step-by-step explanation:

F(x)=x²-3x+2/3x²+9x-12

Using mid term break formula

=x²-2x-x+2/3(x²+3x-4)

=x(x-2)-1(x-2)/3(x²+4x-x-4)

=(x-2)(x-1)/3{x(x+4)-1(x+4)}

=(x-2)(x-1)/3(x-1)(x+4)

Cancelling (x-1)

We get

=(x-2)/3(x+4)

Hope it helps :)

6 0
3 years ago
Is 4 18/12 equal to 5 6/12?
Tom [10]

Answer:

Yes, 4 18/12 is equal to 5 6/12.

Step-by-step explanation:

Given that

4 18/12 = 5 6/12

11/2 = 11/2

Yes both are equal.

7 0
3 years ago
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juin [17]

You idiot you answered your own question!

7 0
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Given that f(x) = x2 – 3x – 28 and g(x) = x - 7, find
gregori [183]

Answer:

(f-g)(x)=x^2-4x-21

Step-by-step explanation:

We are given the two functions:

f(x)=x^2-3x-28\text{ and } g(x)=x-7

And we want to find:

(f-g)(x)

This is equivalent to:

=f(x)-g(x)

Substitute:

=(x^2-3x-28)-(x-7)

Distribute:

=x^2-3x-28-x+7

Rearrange:

=(x^2)+(-3x-x)+(-28+7)

Hence:

(f-g)(x)=x^2-4x-21

6 0
3 years ago
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