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3 years ago

Please help, i did it just dont want to get a bad grade for homework so need somone to double check.

Mathematics

1 answer:

andriy [413]3 years ago

3 0

A. $f(-5)=7+|-5|=12$

B. $g(4)=4^3-5=59$

C. $f(0)=7+|0|=7$

D. $f(2)=7+|2|=9$

E. $g(-2)=-2^3-5=-13$

Hope this helps BangtanBoyScouts

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joja [24]

I think the answer is C

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3 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$

Therefore, the total outcomes for drawing straight are:

$N_S\;=\;({}^{4}C_1)*({}^{4}C_1)^5\;=\;10240$

Thus, the probability of getting a straight hand is:

$P(b)\;=\;\frac{N_S}{N_T}\\\\P(b)\;=\;\frac{10240}{2598960}\\\\P(b)\;=\; 0.0039$

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3 years ago

How do I solve: -(19-3s)-(8s+1)=35

bazaltina [42]

Hi Kimberly!

-(19 - 3s) - (8s + 1) = 35
-19 + 3s -8s - 1 = 35
-19 - 1 + 3s - 8s = 35
-20 - 5s = 35
-5s =35 + 20
-5s = 55
Divide both sides by -5
-5s/-5 = 55/-5
s = -11

A+ for Algebra guaranteed!

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3 years ago

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Lily’s sister has a bag of skittles containing 3 yellow skittles, 4 red skittles, 5 green skittles, and 3 orange skittles. What

lisov135 [29]

Answer:

Read a bit so you can understand which one you want.

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3 over 15, or 0.2 as a percentage.

So there is a 0.8% chance that he will NOT pick an orange skittle.

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3 over 15 can be 1 over 5.

So there is a 4 over 5 chance that he WONT grab an orange skittle, pretty good odds.

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3 years ago

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Klio2033 [76]

Hey. Let me help you on this one.

In order for us to solve this problem, we will be needing to find both length and width of the triangle on this coordinate plane. We will also need to know how to use the triangle area formula.

I will be attaching an image containing the shown difference between a rectangle, and a triangle, and on how to understand why the area of a triangle is like this.

First of all, let's find the length of the triangle. It's 11 units, and we can determine that by counting up all of the units, or simply finding the difference between x-point 13 and 2, which is going to be 11.

Same applies to the width of the triangle. We will need to either count up all the units individually, or find a difference between a higher y-point and lower y-point. That difference is going to 5 units, since $9-4=5$ .

Now, let's use the formula for the triangle area and substitute the values.

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4 years ago

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