The independent variable is always the frist value in an ordered pair ?? True or false

Evelyn has dance class every Saturday. It lasts 1 hour and 40 minutes and is over at 12:45 P.M.

leva [86]

Answer:

Evelyn's dance class on Saturday starts at 11:05 A.M.

Step-by-step explanation:

I know this because if her class takes an hour and 40 minutes you would subtract the hour and 40 minutes from 12:45 so you could do 12 - 1 which equals 11. Then you would do 45 - 40 which equals 5. And last you would put the new times together so it would be, 11:05. Her dance class starts at 11:05 A.M.

7 0

3 years ago

I need help please 36 points

geniusboy [140]

Using the power of zero property, we find that:

a) The simplification of the given expression is 1.

b) Since , equivalent expressions are: and .

--------------------------------

The power of zero property states that any number that is not zero elevated to zero is 1, that is:

Thus, at item a, , thus the simplification is .

At item b, equivalent expressions are found elevating non-zero numbers to 0, thus and .

5 0

2 years ago

PLZ HELP WILL RATE BRAINLIEST REMEMBER IT HAS 5 DIGITS

kobusy [5.1K]

Answer:

i figured it out the number is 12,316 if i am correct

7 0

3 years ago

Read 2 more answers

Find an expression which represents the sum of (7x - 8y) and (-6x - 6y) in simplest terms.

grigory [225]

Answer:

$\displaystyle (7x - 8y) + (-6x - 6y) = x - 14y$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle (7x - 8y) + (-6x - 6y)$

Step 2: Simplify

Combine like terms (x): $\displaystyle (7x - 8y) + (-6x - 6y) = x - 8y - 6y$
Combine like terms (y): $\displaystyle (7x - 8y) + (-6x - 6y) = x - 14y$

3 0

2 years ago

Help with 5b please . thank you.

Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0

2 years ago