Question

If the discriminant is zero in a quadratic formula, determine the number of real solutions for that quadratic formula. Please help.

Answer 1

Keywords

discriminant, quadratic equation, real solution

we know that

The formula to calculate the solutions of the quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}$

where

The discriminant of the quadratic equation  is equal to

$b^{2}-4ac$

in this problem we have  that

$b^{2}-4ac=0$

so

substitute in the formula

$x=\frac{-b(+/-)\sqrt{0}}{2a}$

$x=-\frac{b}{2a}$  -------> is one real solution

therefore

The answer is

one real solution

Answer 2

Answer:

B. one real solution

Step-by-step explanation:

just took the practice