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Oxana [17]
3 years ago
11

Simplify. mn^-4/p^0 q^-2 answer choices: mq^2/n^4 mp/n^4 mn^4 q^2 p^0 q^2/mn^4

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
I would say D but my gut tells me that's wrong but when you work it the ovbs. way that's the only choice that makes sense
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What is the equation of the line that passes through (2, -7) and (-1, 2)?
SVETLANKA909090 [29]

Answer:

y = -3x - 1

Step-by-step explanation:

The slope intercept form of the equation of a line is:

y = mx + b

where m is the slope, and b is the y-intercept.

First, we find the slope of the line using the two given points.

m = slope = (y2 - y1)/(x2 - x1) = (2 - (-7))/(-1 - 2) = (2 + 7)/(-3) = 9/(-3) = -3

Now we plug in the slope we found into the equation above.

y = -3x + b

We need to find the value of b, the y-intercept. We use the coordinates of one of the given points for x and y, and we solve for b. Let's use point (2, -7), so x = 2, and y = -7.

y = -3x + b

-7 = -3(2) + b

-7 = -6 + b

Add 6 to both sides.

-1 = b

Now we plug in -1 for b.

y = -3x - 1

4 0
3 years ago
The graph below is the solution for which set of inequalities?
kipiarov [429]

Answer:

R u in ms Francis class??

Step-by-step explanation:

6 0
3 years ago
Solve the triangle A = 2 B = 9 C =8
VARVARA [1.3K]

Answer:

\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}

Then, given the sides a=2, b=9, and c=8.

\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}

For B:

\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}

3 0
1 year ago
Determine the equation of a circle whose diameter has the endpoints (-1, 2) and (7.
Viefleur [7K]

Answer:

(x - 3)^2 + (y + 1) = 25

Step-by-step explanation:

First find the midpoint of the diameter, because that represents the center of the circle.

                                                                     -1 + 7

The x-coordinate of the midpoint is xm = ---------- = 3

                                                                          2

                                                 2 - 4

and the y-coordinate is ym = ---------- = -1

                                                     2

And so the center of this circle is at (3, -1).

Use the Pythagorean Theorem to determine the square of the radius:

square of radius = 4^2 + (-3)^2 = 16 + 9 = 25

And so the equation of this circle is (x - 3)^2 + (y + 1) = 25

5 0
3 years ago
Read 2 more answers
Simplify.<br><br> 7/8+(−2/3) divided by <br> 5/6
Sedaia [141]
7/8+(−2/3) divided by 5/6

(7/8 - 2/3)/(5/6)
=(21/24 - 16/24) / (5/6)
= (5/24)  /  (5/6)
= 5/24 * 6/5
= 6/24
= 1/4
7 0
4 years ago
Read 2 more answers
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