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Law Incorporation [45]
2 years ago
6

HELP!! Determine whether the pair of lines are parallel, perpendicular, or neither. 8x=3y+2 -16x+6y=2.

Mathematics
1 answer:
EleoNora [17]2 years ago
6 0

Answer:

24x - 9y=0

Step-by-step explanation:

8x=3y+2-16x+6y=2

8x=9y+2-16x=2

8x+16-9y=2-2

24x-9y=0

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GarryVolchara [31]

Answer:   x < 2

<u>Step-by-step explanation:</u>

2x + 1 < 5

Subtract 1 from both sides:

2x < 4

Divide both sides by 2:

x < 2     <em>(x is less than 2)</em>

Graph:    ←-------o -2

Interval Notation: (-∞, -2)

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2 years ago
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Answer:

3/2

Step-by-step explanation:

My reasoning is that the sum of the numbers in the left is equal to the sum of the numbers in the right.

Therefore 6=2y+3

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3

Step-by-step explanation:

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2 years ago
Josh has $25 and he wants to buy some movies. He picks one movie that costs $9.99 and two that cost $5.99 each.
vova2212 [387]
He should add exact since money is involved
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3 0
3 years ago
Read 2 more answers
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
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