Find f(2), f(0), f(-1)

Mathematics

1 answer:

mr Goodwill [35]4 years ago

7 0

Put the values of x to the equation of the function f:

$f(x)=\dfrac{x+21}{9x-3}\\\\f(2)=\dfrac{2+21}{9(2)-3}=\dfrac{23}{18-3}=\dfrac{23}{15}\\\\f(0)=\dfrac{0+21}{9(0)-3}=\dfrac{21}{-3}=-7\\\\f(-1)=\dfrac{-1+21}{9(-1)-3}=\dfrac{20}{-9-3}=\dfrac{20}{-12}=-\dfrac{5}{3}$

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