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erik [133]
3 years ago
12

GETS BRAINLIEST AND 11 PTS!

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
The answer would be group A, hope this helps.
noname [10]3 years ago
3 0
See the attached picture:

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Can you give me the answer
Mnenie [13.5K]

Answer: B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
X=25.36+0.45(25.36)<br><br> LaTeX: x=
e-lub [12.9K]

Answer:

x=36.772  

Step-by-step explanation:

Given : Expression x=25.36+0.45(25.36)

To find : Solve the expression ?

Solution :

Step 1 - Write the expression,

x=1(25.36)+0.45(25.36)

Step 2 - Apply distributive, ab+ac=a(b+c)

Here, a=25.36, b=1, c=0.45

x=25.36(1+0.45)

Step 3 - Solve the expression,

x=25.36\times 1.45

x=36.772

Therefore, x=36.772

7 0
4 years ago
Expand the following log:<br><br><br><img src="https://tex.z-dn.net/?f=log_%7B3%7D%20%28x%5E%7B4%7D%20y%29" id="TexFormula1" tit
devlian [24]

Answer:

\log_{3}(x^4y)=4\log_{3}(x)+\log_{3}(y)

Step-by-step explanation:

The given logarithmic expression is

log_{3}(x^4y)

Recall and use the product property of logarithm: \log_a(MN)=\log_a(M)+\log_a(N);

This implies that;

\log_{3}(x^4y)=\log_{3}(x^4)+\log_{3}(y)

Recall again that; \log_a(M^n)=n\log_a(M);

We apply this property to get;

\log_{3}(x^4y)=4\log_{3}(x)+\log_{3}(y)

5 0
4 years ago
Please answer it now in two minutes
scZoUnD [109]

Answer: 8 yd

Step-by-step explanation:

The dotted triangle is a right triangle, the distance on the top of the triangle is the same distance as WZ

6 0
3 years ago
Find the explicit formula that produces the given sequence. <br> 3/2, 3/4, 3/8, 3/16,...
lara [203]
\frac{3}{2};\ \frac{3}{4};\ \frac{3}{8};\ \frac{3}{16};\ ...\\\\a_1=\frac{3}{2}\\\\a_2=\frac{3}{4}=\frac{3}{2}\cdot\frac{1}{2}\\\\a_3=\frac{3}{8}=\frac{3}{4}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^2\\\\a_4=\frac{3}{16}=\frac{3}{8}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^3\\\vdots
a_n=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{n-1}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{-1}\cdot\left(\frac{1}{2}\right)^n=\frac{3}{2}\cdot2\cdot\left(\frac{1}{2}\right)^n=3\cdot\left(\frac{1}{2}\right)^n
7 0
3 years ago
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