Need a quick answer please

Mathematics

1 answer:

Zanzabum3 years ago

4 0

Answer:

8 fits the equation

Step-by-step explanation:

hope this helps

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Help me pleaseeeeeeeeee

leonid [27]

A is the answer i think

if not then c

5 0

3 years ago

The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard form below.

saw5 [17]

Answer:

$x^2 + x -12$

Step-by-step explanation:

If the solutions are x=-4 and x=3, then it must have factors (x+4)(x-3). Assuming there is no GCF or leading coefficient other than 1, multiply with FOIL to find the standard form.

$(x+4)(x-3)\\x^2 + 4x -3x -12\\x^2 + x -12$

7 0

3 years ago

Read 2 more answers

Simplify: –4(x – 5) + 3(a – 7)

Serga [27]

-4 (x - 5) + 3 (a - 7)

First, expand your problem. / Your problem should look like: -4x + 20 + 3a - 21
Second, simplify. / Your problem should look like: -4x + 3a - 1

Answer: -4x + 3a - 1 (C)

8 0

3 years ago

Read 2 more answers

(-4,5) and (4,0) find the distance between each pair of points

aleksklad [387]

Answer:

9.4339 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$